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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

2. Areas of Trapezoids, Rhombuses, and Kites

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Exercise 22 Page 626

The area of a kite is half the product of its diagonals.

24ft^2

Practice makes perfect

The area of a kite is half the product of its diagonals. Therefore, we can find the area of a kite when we know the lengths of its diagonals.

In the diagram we see that the vertical diagonal has a length of d_1= 6 feet. To find the length of horizontal diagonal we will use the Segment Addition Postulate. d_2: 4 + 4 = 8 feet Using the diagonal lengths, let's find the area of the kite.

A=1/2d_1 d_2

d_1= 6, d_2= 8

A=1/2( 6)( 8)

▼

Evaluate right-hand side

Multiply

A=1/2(48)

MoveRightFacToNumOne

1/b* a = a/b

A=48/2

Calculate quotient

A=24

The area of the kite is 24ft^2.

Subchapter links

Lesson Check p.625

Practice and Problem-Solving Exercises p.626-628

Standardized Test Prep p.628

Mixed Review p.628