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Pearson Geometry Common Core, 2011

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Pearson Geometry Common Core, 2011 View details

2. Areas of Trapezoids, Rhombuses, and Kites

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Exercise 6 Page 625

The area of a kite is half the product of the lengths of its diagonals.

8cm^2

Practice makes perfect

The area of a kite is half the product of the lengths of its diagonals. Let's consider the given diagram.

By the Segment Addition Postulate, the length of the horizontal diagonal is 2+2= 4 centimeters and the vertical diagonal has a length of 3+1=4 centimeters. Using the diagonal lengths, let's find the area of the kite.

A=1/2d_1 d_2

d_1= 4, d_2= 4

A=1/2( 4)(4)

▼

Evaluate right-hand side

MoveRightFacToNumOne

1/b* a = a/b

A=(4)(4)/2

a/b=.a /2./.b /2.

A=2(4)

Multiply

A=8

The area of the kite is 8 cm^2.

Subchapter links

Lesson Check p.625

Practice and Problem-Solving Exercises p.626-628

Standardized Test Prep p.628

Mixed Review p.628