After plotting the points on a coordinate plane, connect them to see the type of curve that best fits them.
Graph:
Model: Quadratic
Practice makes perfect
We want to determine the most appropriate model for the given data set.
(- 2,5), (- 1, - 1), (0,- 3), (1,- 1), (2,5)
To do so we will plot and connect the given points on a coordinate plane. Then we can see the type of curve that best fits.
We see that the curve that best fits the points is a parabola. Therefore, the most appropriate model for the data set is a quadratic model. Let's now remove the curve and leave only the given points.
Extra
Linear, Quadratic, and Exponential Models
In this exercise, we have chosen the quadratic model as the most appropriate model for the given set of points. The quadratic model models the set of points with the function y = ax^2 +bx+c. There are two more models that we know. Let's recall them.
Exponential Model
When choosing the exponential model, we model the set of points with the function y = a * b^x. Consider the following set of points.
(0,2), (-1, 4), (1,1), (2, 0.5)
The most appropriate model for this set is the exponential model. We can see it by graphing the points on the coordinate plane.
Linear Model
When choosing the linear model, we model the set of points with the function y = mx+b. Consider the following set of points.
(-1,-2), (0, -1), (1,0), (3, 2)
The most appropriate model for this set is the linear model. We can see it by graphing the points on the coordinate plane.
