Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. Linear, Quadratic, and Exponential Models
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Exercise 19 Page 593

Check the ratios of the values of the balance. What do your results mean?

Model: Exponential
Equation: y=540(1.03)^x

Practice makes perfect

We will start by determining the type of function that best models the data. Then we will be able to write an exact equation that models the data.

Finding a Model

We want to find the most appropriate model for the given data set. Note that the numbers of the month have a common difference of 1. Therefore, we can check if the values of the balance have a common difference, a common ratio, or constant second differences. It will tell us which model is most appropriate for the data set.

The values of the attendance have: The model is:
A common difference Linear
A common ratio Exponential
Constant second differences Quadratic
Sometimes data does not fall exactly into the models listed above. In this case we have to round our results and see when they are the closest to being constant. Let's start by checking our data set for a common difference!
Month Balance ($) First differences
0 540
1 556.20 +16.20 ↩
2 572.89 +16.69 ↩
3 590.07 +17.18 ↩
4 607.77 +17.70 ↩

As we can see, the differences between the consecutive values of the balance oscillate between 16.20 and 17.70. Even though these values are pretty close, we would like them to be closer! Therefore, we will check for a common ratio next.

Month Balance ($) Ratio
0 540
1 556.20 556.20/540=1.03
2 572.89 572.89/556.20=1.030...
3 590.07 590.07/572.89=1.029...
4 607.77 607.77/590.07=1.029...

The ratios between the consecutive values of the balance are all approximately 1.03, so an exponential model fits the data.

Writing an Equation

We know that an exponential function best models the balance. y= a* b^x To write an equation to model the data, we have to determine the values of a and b. Recall that (0, a) is the y-intercept of the exponential function. Since the pair (0,540) is included in the data set, a= 540. y= 540* b^x In order to determine the value of b we will use one (x,y) pair from the data set, other than (0,540), to write an equation. Let's use ( 1, 556.20).
y=540* b^x
556.20=540* b^1
â–Ľ
Solve for b
556.20=540* b
1.03=b
b= 1.03
We have that b= 1.03. Note that the value of b is equal to the approximation of the common ratio! We could have used that information instead of solving the equation. Let's finish writing the equation to model the data! y= 540* 1.03^x ⇔ y=540(1.03)^x