Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
7. Linear, Quadratic, and Exponential Models
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Exercise 21 Page 593

Practice makes perfect
a

We are asked to choose five x-values and use them to find the second differences of each of the given functions. We will start with the quadratic function shown below.

i. f(x)=x^2-3 First we need to choose the x-values we will use. For example, x=-2, x= -1, x=0, x=1, and x=2. Now we can use a table to find the corresponding function's values.

x f(x)=x^2-3 Simplify
- 2 f( - 2) = ( - 2)^2-3 f( - 2) = 1
- 1 f( - 1) = ( - 1)^2-3 f( - 1) = - 2
0 f( 0) = ( 0)^2-3 f( 0) = - 3
1 f( 1) = ( 1)^2-3 f( 1) = - 2
2 f( 2) = ( 2)^2-3 f( 2) = 1
We can create a second table with the x-values and the corresponding function's values we just found. To find the first differences, we need to take pairs of the function's values and find their difference.

If we repeat the process by taking pairs of first differences and subtract them, we can find the second differences.

As we can see, the second differences are a common constant. We need to repeat the same process for the second function. ii. f(x) = 3x^2

Finally, let's do the same for the third function. ii. f(x) = 4x^2-5x

b

Let's take a look at the results from Part A.

Function Common second difference
f(x) = 1x^2-3 2 = 2* 1
f(x) = 3x^2 6 = 2* 3
f(x) = 4x^2-5x 8 = 2* 4

As we can see, the common second differences are equal to the coefficient of the x^2-term times two.

c

According to the results found in Parts A and B, if a set of data pairs has common second differences we know that it fits a quadratic function. Furthermore, we could divide the common second difference by two to find the value of the x^2-term's coefficient.