Sign In
Evaluate the quadratic functions given and then find the difference between consecutive pairs of the function's values, these are the first differences.
Take a look at the results found in Part A. Can you identify any pattern relating the x^2-term coefficient and the common second differences?
What can we tell by using the relationship found in Part B? How can it be used for a data set with common second differences?
i. f(x) = x^2-3
ii. f(x) = 3x^2
iii. f(x) = 4x^2-5x
See solution.
See solution.
We are asked to choose five x-values and use them to find the second differences of each of the given functions. We will start with the quadratic function shown below.
i. f(x)=x^2-3 First we need to choose the x-values we will use. For example, x=-2, x= -1, x=0, x=1, and x=2. Now we can use a table to find the corresponding function's values.
| x | f(x)=x^2-3 | Simplify |
|---|---|---|
| - 2 | f( - 2) = ( - 2)^2-3 | f( - 2) = 1 |
| - 1 | f( - 1) = ( - 1)^2-3 | f( - 1) = - 2 |
| 0 | f( 0) = ( 0)^2-3 | f( 0) = - 3 |
| 1 | f( 1) = ( 1)^2-3 | f( 1) = - 2 |
| 2 | f( 2) = ( 2)^2-3 | f( 2) = 1 |
If we repeat the process by taking pairs of first differences and subtract them, we can find the second differences.
As we can see, the second differences are a common constant. We need to repeat the same process for the second function. ii. f(x) = 3x^2
Finally, let's do the same for the third function. ii. f(x) = 4x^2-5x
Let's take a look at the results from Part A.
| Function | Common second difference |
|---|---|
| f(x) = 1x^2-3 | 2 = 2* 1 |
| f(x) = 3x^2 | 6 = 2* 3 |
| f(x) = 4x^2-5x | 8 = 2* 4 |
As we can see, the common second differences are equal to the coefficient of the x^2-term times two.
According to the results found in Parts A and B, if a set of data pairs has common second differences we know that it fits a quadratic function. Furthermore, we could divide the common second difference by two to find the value of the x^2-term's coefficient.