Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. Linear, Quadratic, and Exponential Models
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Exercise 24 Page 593

Check the ratios of the numbers of frogs. What do your results mean?

Model: Exponential
Equation: y=120(0.8)^x

Practice makes perfect

We will start by determining the type of function that best models the data. Then we will be able to write an exact equation that models the data.

Finding a Model

We want to find the most appropriate model for the given data set. Note that the years have a common difference of 1. Therefore, we can check if the numbers of frogs have a common difference, a common ratio, or constant second differences. It will tell us which model is most appropriate for the data set.

The values of the attendance have: The model is:
A common difference Linear
A common ratio Exponential
Constant second differences Quadratic
Sometimes data does not fall exactly into the models listed above. In this case we have to round our results and see when they are the closest to being constant. Let's start by checking our data set for a common difference!
Year Number of Frogs First Differences
0 120
1 101 -19 ↩
2 86 -15 ↩
3 72 -14 ↩
4 60 -12 ↩

As we can see, the differences between the consecutive numbers of frogs are far from being constant. Therefore, we will check for a common ratio next.

Year Number of Frogs Ratio
0 120
1 101 101/120=0.841...
2 86 86/101=0.851...
3 72 72/86=0.837...
4 60 60/72=0.833...

The ratios between the consecutive values of the balance are all roughly 0.8, so an exponential model fits the data.

Writing an Equation

We know that an exponential function best models the number of frogs. y=a*b^x To write an equation to model the data we have to determine the values of a and b. Recall that (0,a) is the y-intercept of the exponential function. Since the pair (0,120) is included in the data set, a=120. y=120*b^x In order to determine the value of b we will use one (x,y) pair from the data set, other than (0,120), to write an equation. Let's use ( 1, 101).
y=120* b^x
101=120* b^1
Solve for b
120* b^1=101
120* b=101
b=0.841...
b≈0.8
We have that b≈0.8. Note that the value of b is equal to the approximation of the common ratio! We could have used that information instead of solving the equation. Let's finish writing the equation to model the data! y=120*0.8^x ⇔ y=120(0.8)^x