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Pearson Algebra 1 Common Core, 2011 View details

3. Slope-Intercept Form

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Exercise 73 Page 314

Start by using the Subtraction Property of Equality.

x=7

Practice makes perfect

To solve the equation, we have to isolate x on one side. We will begin by subtracting 5 from both sides. This is allowed by the Subtraction Property of Equality.

8x+5=61

SubEqn

LHS-5=RHS-5

8x+5-5=61-5

SubTerms

Subtract terms

8x=56

Now that the x term is isolated, we will use the Division Property of Equality to eliminate the coefficient 8.

8x=56

DivEqn

.LHS /8.=.RHS /8.

x=7