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Try to rewrite this inequality as a compound inequality.
D
We can split this compound inequality into two cases, one where 2x+5 is greater than or equal to -3 and one where 2x+5 is less than or equal to 3. 2x+5≥- 3 and 2x+5≤ 3 Let's isolate x in both of these cases before graphing the solution set.
LHS-5≥RHS-5
.LHS /2.≥.RHS /2.
Rearrange inequality
The solution to this type of compound inequality is the overlap of the solution sets. Let's combine our cases back into one compound inequality. First Solution Set:& - 4≤ x Second Solution Set:& x≤- 1 Intersecting Solution Set:& - 4≤ x≤- 1
The graph of this inequality includes all values from - 4 to - 1, inclusive. We show this by using closed circles on the endpoints.
The correct choice is D.