Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
3. Slope-Intercept Form
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Exercise 67 Page 314

Sometimes

Practice makes perfect

We have been told that a, b, and c are real numbers, a ≠ 0, and b>c. We are asked to decide whether the statement ab>ac is always, sometimes, or never true. For this statement we have two cases.

  • Case I: a is greater than 0.
  • Case II: a is smaller than 0.

We will begin with a is greater than 0.

Case I: a>0

Let's check whether the statement is true if a>0. To do this, let's first try with arbitrarily chosen values for a, b, and c, such as a= 2, b= 4, and c= 3.
4> 3
4 * 2 > 3 * 2
8>6
It worked! This will be the case for any positive value of a thanks to the Multiplication Property of Inequality.
b>c
ba>ca
ab>ac
As we can see, the statement is true for a>0. What about the second case?

Case II: a<0

What happens if a<0? Remember that if we multiply an inequality by a negative number we need to reverse the inequality symbol by the Multiplication Property of Inequality. Once again, let's try with arbitrarily chosen values for a, b, and c, such as a= -2, b= 4, and c= 3.
4> 3
-2* 4< -2* 3
-8<-6
This result tells us that for a negative value of a the opposite of what we want to be true is true. ab > ac * ab < ac âś“ Thus, when a<0, the statement is false. As a result, we say that the original statement is sometimes true.