Exercise 37 Page 190

We can solve inequalities in almost the same way as equations. The only difference is that we need to remember to flip the inequality sign when multiplying or dividing by a negative value. For this exercise, distribute 3 on the left-hand side and simplify the terms to isolate t.

3(2+t)≥15-2t

Distr

Distribute 3

6+3t≥15-2t

AddIneq

LHS+2t≥RHS+2t

6+5t≥15

SubIneq

LHS-6≥RHS-6

5t≥9

DivIneq

.LHS /5.≥.RHS /5.

t≥9/5

The solution to the inequality is t≥ 95.