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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

4. Solving Multi-Step Inequalities

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Exercise 59 Page 192

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

x=3

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality.

2x+8=4x+2

LHS-2x=RHS-2x

2x+8-2x=4x+2-2x

Subtract term

8=2x+2

LHS-2=RHS-2

8-2=2x+2-2

Subtract term

6=2x

.LHS /2.=.RHS /2.

6/2=2x/2

Calculate quotient

3=x

Rearrange equation

x=3

The solution to the equation is x=3.

Checking Our Answer

Checking Our Answer

We can check our solution by substituting it into the original equation.

2x+8=4x+2

x= 3

2* 3+8? =4* 3+2

Multiply

6+8? =12+2

Add terms

14=14

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Lesson Check p.189

Practice and Problem-Solving Exercises p.190-192

Standardized Test Prep p.192

Mixed Review p.192