Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
4. Solving Multi-Step Inequalities
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Exercise 48 Page 191

Example Solution (I): -5x+3 > -7
Example Solution (II): -5x+3 ≤ 18

Practice makes perfect

In this exercise, we are asked to write two different inequalities that can be solved by subtracting 3 from each side and then dividing each side by -5. In order to do that, we will need two different solution sets and we will apply inverse operations to create the solvable inequalities.

Possible Inequality (I)

Let's assume our solution set to the Inequality (I) is x<2 and use inverse operations to write the inequality that has the solution set x<2. Our first step to write the inequality will be the inverse of the last step of the solution. We will multiply each side by -5.
x<2
-5* x > -5 * 2
-5x > -10
Now, our second step to write the inequality will be the inverse of the first step of the solution. We will add 3 to each side.
-5x > -10
-5x+3 > -10+3
-5x+3 > -7
The first possible inequality is -5x+3 > -7.

Checking Our Answer

Checking Our Answer
Now, let's solve it by following the given instructions to check the solution.
-5x+3 > -7
-5x > -10
-5x/-5<-10/-5
x<2
The inequality satisfies the solution.

Possible Inequality (II)

For the second possible inequality, assume that our solution is x≥ -3. Let's write the second inequality by following the same process as we did with Inequality (I).
x≥ -3
-5* x ≤ -5* (-3)
-5x ≤ -5* (-3)
-5x ≤ 15
-5x+3 ≤ 15+3
-5x+3 ≤ 18
The second possible inequality is -5x+3 ≤ 18.

Checking Our Answer

Checking Our Answer
Now, let's solve it by following the given instructions to check the solution.
-5x+3 ≤ 18
-5x ≤ 15
-5x/-5≥15/-5
5x/5≥15/-5
5/5* x≥-15/5
x ≥ -3
The inequality satisfies the solution.