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Use inverse operations.
Example Solution (I): -5x+3 > -7
Example Solution (II): -5x+3 ≤ 18
In this exercise, we are asked to write two different inequalities that can be solved by subtracting 3 from each side and then dividing each side by -5. In order to do that, we will need two different solution sets and we will apply inverse operations to create the solvable inequalities.
Let's assume our solution set to the Inequality (I) is x<2 and use inverse operations to write the inequality that has the solution set x<2. Our first step to write the inequality will be the inverse of the last step of the solution. We will multiply each side by -5.
Multiply by -5 and flip inequality sign
(- a)b = - ab
The first possible inequality is -5x+3 > -7.
LHS-3>RHS-3
Divide by -5 and flip inequality sign
Calculate quotient
The inequality satisfies the solution.
For the second possible inequality, assume that our solution is x≥ -3. Let's write the second inequality by following the same process as we did with Inequality (I).
Multiply by -5 and flip inequality sign
a(- b)=- a * b
- a(- b)=a* b
LHS+3≤RHS+3
Add terms
The second possible inequality is -5x+3 ≤ 18.
LHS-3≤RHS-3
Divide by -5 and flip inequality sign
- a/- b=a/b
Put minus sign in front of fraction
Calculate quotient
The inequality satisfies the solution.