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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

4. Solving Multi-Step Inequalities

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Exercise 11 Page 190

Begin by isolating y on the left-hand side.

y>-2

Practice makes perfect

Let's isolate y to solve the inequality.

-5y-2<8

LHS+2

-5y<10

Divide by -5 and flip inequality sign

y>-2

The solution y>-2 means that any number greater than -2 will satisfy the inequality.

Checking Our Answer

Checking Our Answer

Let's check this by choosing an arbitrary value for y and plugging it into the original inequality. Let's choose 0 for y. We know that 0 > - 2, so we should expect a true result.

-5y-2<8

y= 0

-5* 0-2 ? < 8

Multiply

-2<8

This result is true. Our inequality is correct for this test value.

Subchapter links

Lesson Check p.189

Practice and Problem-Solving Exercises p.190-192

Standardized Test Prep p.192

Mixed Review p.192