Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Literal Equations and Formulas
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Exercise 49 Page 114

Practice makes perfect
a We are given a rectangular prism with height h and square bases with side length s, as shown in the figure below. Let's find a formula for its surface area!

From the figure, we can see that as the base is a square of side s, its area will be given as s * s = s^2. Notice we will have 2 of these. Also, we have 4 rectangular, lateral sides of base s and length h. Their area will be given by h * s. Then, the total surface area will be given by the expression A = 2s^2 + 4hs.


b Now, we want to rewrite the surface area formula to find h in terms of A and s. In Part A, we found that the surface area is given by A = 2s^2 + 4hs. Let's solve for h using inverse operations.
A = 2s^2 + 4hs
A - 2s^2 = 4hs
A - 2s^2/4s = h
h = A - 2s^2/4s
Now that we found the expression for h, we can determine the height if the prism were to have an area of 760 cm^2 and a base side length of s=10cm. Let's substitute these values in our formula and simplify.
h = A - 2s^2/4s
h = 760 cm^2 - 2( 10 cm)^2/4( 10 cm)
h = 760 cm^2 - 2(100 cm^2)/4(10 cm)
h = 760 cm^2 - 200 cm^2/40 cm
h = 560 cm^2/40 cm
h = 14 cm
The height would be 14cm.
c Next, we can rewrite the formula from Part A to see what it would look like in terms of s for the case when h=s. Let's substitute h=s in the formula and simplify.
A = 2s^2 + 4hs
A = 2s^2 + 4* s* s
A = 2s^2 + 4s^2
A = 6s^2

When h=s, the surface area will be 6 times the area of one of its faces. This is because, in this case, all sides are the same length. This is a cube.