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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

5. Literal Equations and Formulas

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Exercise 15 Page 112

Isolate y on the left-hand side of the equation, then substitute the values for x.

Equation: y=4-5x/4

x	y
1	-1/4
2	-3/2
3	-11/4

Practice makes perfect

Let's begin by solving the equation for y.

5x=-4y+4

LHS-4=RHS-4

5x-4=-4y+4-4

Subtract terms

5x-4=-4y

.LHS /-4.=.RHS /-4.

5x-4/-4=-4y/-4

- a/- b=a/b

-5x+4/4=4y/4

a/b=.a /4./.b /4.

-5x+4/4=y

CommutativePropMult

Commutative Property of Multiplication

y=4-5x/4

To find the value of y for each of the x-values, we substitute them into the equation and evaluate.

x	4-5x/4	y
1	4-5( 1)/4	-1/4
2	4-5( 2)/4	-3/2
3	4-5( 3)/4	-11/4

Subchapter links

Lesson Check p.112

Practice and Problem-Solving Exercises p.112-114

Standardized Test Prep p.114

Mixed Review p.114