Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Literal Equations and Formulas
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Exercise 14 Page 112

Isolate y on the left-hand side of the equation and substitute the values for x.

Equation: y=4x+7/3

x y
4 23/3
5 27/3
6 31/3
Practice makes perfect
Let's begin by solving the equation for y.
4x=3y-7
4x+7=3y-7+7
4x+7=3y
4x+7/3=3y/3
4x+7/3=y
y=4x+7/3
To find the value of y for each of the x-values, we substitute them into the equation and evaluate.
x 4x+7/3 y
4 4( 4)+7/3 23/3
5 4( 5)+7/3 27/3
6 4( 6)+7/3 31/3