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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

5. Literal Equations and Formulas

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Exercise 16 Page 112

Isolate y on the left-hand side of the equation, then substitute the values for x.

Equation: y=4-7x/2

x	y
5	- 31/2
10	- 33
15	- 101/2

Practice makes perfect

Let's begin by solving the equation for y.

2y+7x=4

LHS-7x=RHS-7x

2y+7x-7x=4-7x

Subtract terms

2y=4-7x

.LHS /2.=.RHS /2.

2y/2=4-7x/2

a/b=.a /2./.b /2.

y=4-7x/2

To find the value of y for each of the x-values, we substitute them into the equation and evaluate.

x	4-7x/2	y
5	4-7( 5)/2	-31/2
10	4-7( 10)/2	-33
15	4-7( 15)/2	- 101/2

Subchapter links

Lesson Check p.112

Practice and Problem-Solving Exercises p.112-114

Standardized Test Prep p.114

Mixed Review p.114