Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Literal Equations and Formulas
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Exercise 12 Page 112

Isolate y on the left-hand side of the equation, then substitute the values for x.

Equation: y=4-2x

x y
- 2 8
1 2
3 - 2
Practice makes perfect

Let's begin by solving the equation for y.

2y+4x=8
2y+4x-4x=8-4x
2y=8-4x
2y/2=8-4x/2
2y/2=2(4-2x)/2
y=4-2x

To find the value of y for each of the x-values, we substitute them into the equation and evaluate.

x 4-2x y
- 2 4-2( - 2) 8
1 4-2* 1 2
3 4-2* 3 - 2