Exercise 52 Page 114

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, the variable term is already on the left-hand side of the equation, so we will start by subtracting terms.

9p+6-3p=45

SubTerms

Subtract terms

6p+6=45

SubEqn

LHS-6=RHS-6

6p+6-6=45-6

SubTerms

Subtract terms

6p=39

DivEqn

.LHS /6.=.RHS /6.

6p/6=39/6

ReduceFrac

a/b=.a /6./.b /6.

p=13/2

FracToMixed

Write fraction as a mixed number

p=6 12

The solution to the equation is p = 6 12.