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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

5. Literal Equations and Formulas

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Exercise 52 Page 114

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

p=6 12

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, the variable term is already on the left-hand side of the equation, so we will start by subtracting terms.

9p+6-3p=45

Subtract terms

6p+6=45

LHS-6=RHS-6

6p+6-6=45-6

Subtract terms

6p=39

.LHS /6.=.RHS /6.

6p/6=39/6

a/b=.a /6./.b /6.

p=13/2

Write fraction as a mixed number

p=6 12

The solution to the equation is p = 6 12.

Subchapter links

Lesson Check p.112

Practice and Problem-Solving Exercises p.112-114

Standardized Test Prep p.114

Mixed Review p.114