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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

5. Literal Equations and Formulas

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Exercise 17 Page 112

Isolate y on the left-hand side of the equation, then substitute the values for x.

Equation: y=4+x/4

x	y
- 2	1/2
4	2
6	5/2

Practice makes perfect

Let's begin by solving the equation for y.

x-4y=-4

LHS-x=RHS-x

x-4y-x=-4-x

Subtract terms

-4y=-4-x

.LHS /-4.=.RHS /-4.

-4y/-4=-4-x/-4

- a/- b=a/b

4y/4=4+x/4

a/b=.a /4./.b /4.

y=4+x/4

To find the value of y for each of the x-values, we substitute them into the equation and evaluate.

x	4+x/4	y
- 2	4+( -2)/4	1/2
4	4+ 4/4	2
6	4+ 6/4	5/2

Subchapter links

Lesson Check p.112

Practice and Problem-Solving Exercises p.112-114

Standardized Test Prep p.114

Mixed Review p.114