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Pearson Algebra 1 Common Core, 2011 View details

Chapter Review

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Exercise 6 Page 153

Start by using the Subtraction Property of Equality.

- 7

Practice makes perfect

To solve the equation, we have to isolate x on one side. We will begin by subtracting 5 from both sides. This is allowed by the Subtraction Property of Equality.

x+5=- 2

SubEqn

LHS-5=RHS-5

x+5-5=- 2-5

SubTerms

Subtract terms

x=- 7

Therefore, x=- 7 is the solution to the equation. To check that we have the correct solution, we can substitute x=- 7 into the original equation and simplify.

x+5=- 2

Substitute

x= - 7

- 7+5? =- 2

AddTerms

Add terms

- 2=- 2

Since the left-hand side and the right-hand side are equal, x=- 7 is a correct solution.