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| 13 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Ignacio got a part-time job at a restaurant. His first task is to peel some garlic. Ms. Ley, the restaurant owner, tells him to peel all the heads of garlic in a crate.
Commutative Property of Multiplication
Associative Property of Multiplication
a^m*a^n=a^(m+n)
Commutative Property of Multiplication
a^m*a^n=a^(m+n)
Multiply
Ignacio is helping Ms. Ley make hand-pulled noodles.
2*2 = 2^2 Ms. Ley told Ignacio to fold and stretch the noodles four more times. 2* 2 * 2 * 2 = 2^4 Notice that the power corresponds to the number of times Ignacio has stretched and folded, or doubled, the noodles. Since the entire amount of noodles is being doubled each time the dough is folded, the two monomials are multiplied. 2^2 * 2^4 The Product of Powers Property can be used to add the powers. 2^2 * 2^4 = 2^6 This numeric expression represents that Ignacio folding and stretching the noodles six times.
2^6 Multiply 2 by itself six times to evaluate this numerical expression. 2^6 &= 2*2*2*2*2*2 &= 64 This means that Ignacio made 64 noodles by folding and stretching the dough six times.
To encourage Ignacio to keep doing a great job, Ms. Ley gives him a bonus each time he gets a compliment from a customer.
This bonus is a small percent increase of his normal total wage for the day. Ignacio does not know how much this percentage is, so he thinks of it as x. This means that if he gets three compliments, his payment is multiplied by x three times. x* x* x = x^3 Ignacio gets two compliments from Table 1, four compliments from Table 2, and one compliment from Table 3. He writes an expression to show his compliment bonus for the day. x^2* x^4* x
x^2* x^4* x ⇓ x^2 * x^4 * x^1 Use the Product of Powers Property to multiply the monomials by adding the exponents. x^2 * x^4 * x^1 &= x^(2+4+1) &= x^7 This means that Ignacio will get a bonus of x^7. The degree of this monomial is 7. Notice that this is also the total number of compliments Ignacio got from all the tables. This is because the percentage bonus is applied each time he receives the a compliment.
Associative Property of Multiplication
Commutative Property of Multiplication
a* a=a^2
Associative Property of Multiplication
a^m*a^n=a^(m+n)
Multiply
Everyone has bad days and today was no exception. In addition to the four compliments from the customers, Ignacio also got two complaints.
Unfortunately, Ms. Ley is very strict and told Ignacio that for each complaint she receives about him, she would cancel out one of the compliment bonuses he gets. This situation can be represented with the following division of monomials. x^4/x^2
x^4/x^2 The Quotient of Powers Property can be used to divide the monomials because the bases are the same. Do this by subtracting the exponent of the denominator from the exponent of the numerator. x^4/x^2 &= x^(4-2) &= x^2 This means that Ignacio will only get the bonus from two compliments. Be more careful the next time, Ignacio!
x^4y^3/x^2y^2 = x^4/x^2 * y^3/y^2 Next, use the Quotient of Powers Property for each division. x^4/x^2 * y^3/y^2 &= x^(4-2) * y^(3-2) &= x^2 * y^1 Any number raised to the power of 1 is equal to itself. x^2 * y^1 = x^2 * y Finally, multiply the monomials. x^2 * y = x^2y The degree of the resulting monomial is the sum of the exponents of its variable factors. 2+1=3 This means that the degree of the monomial is 3. Ignacio got a total of three bonuses. Not too bad, but Ignacio is determined to do better!
It is time to make dumplings! Ignacio wants to help Ms. Ley with the dough. He plans to roll it out and cut it into small squares.
The following monomial shows how many squares Ignacio will have after cutting the dough sheet into an x-by-x grid. x^2
Ignacio was asked to peel all the heads of garlic in the crate.
Associative Property of Multiplication
Commutative Property of Multiplication
Associative Property of Multiplication
a^m*a^n=a^(m+n)
Multiply
Information is stored on electronic devices in the form of bytes. Because applications contain tons of information, this is measured in gigabytes rather than bytes. One gigabyte is equivalent to 2^(30) bytes. 1gigabyte =2^(30)bytes
We are told that 1 gigabyte is equivalent to 2^(30) bytes. Multiply this number by 2 to find how many bytes are in 2 gigabytes. 2^(30) * 2 All of the answer options are powers of 2, so let's write our answer the same way. We can use the Product of Powers Property to do this. First, recall that if no power is written on a number, the power is assumed to be 1. Let's can rewrite 2 as 2^1. 2^(30) * 2 = 2^(30) * 2^1 We can now apply the Product of Powers Property. 2^(30) * 2^1 &= 2^(30+ 1) &= 2^(31) We found that there are 2^(31) bytes in 2 gigabytes.
We can find how many bytes there are in 8 gigabytes in a similar fashion. We first need to write 8 as a power of 2.
8= 2^3
There are 2^(30) bytes in 1 gigabyte. Multiply this number by 8=2^3 to find how many bytes there are in 8 gigabytes.
2^(30) * 8 = 2^(30) * 2^3
We can now use the Product of Powers Property.
2^(30) * 2^3 &= 2^(30+ 3)
&= 2^(33)
This means that there are 2^(33) bytes in 8 gigabytes.
Information is stored on electronic devices in the form of bytes. Nowadays, applications contain tons of information, so it is measured in gigabytes rather than bytes. One gigabyte is equivalent to 2^(30) bytes. 1gigabyte =2^(30)bytes A long time ago, applications contained way less information, so they were often stored on devices known as floppy disks. A floppy disk can store up to 2^(21) bytes of information.
We are asked to find how many floppy disks would be required to store one gigabyte of information. We know told that 1 gigabyte is equivalent to 2^(30) bytes. 1gigabyte =2^(30)bytes One floppy disk can hold up to 2^(21) bytes of information. We can divide 1 gigabyte by this amount to calculate how many increments of 2^(21) bytes are in 2^(30) bytes. 1gigabyte/2^(21)bytes = 2^(30)bytes/2^(21)bytes Next, let's use the Quotient of Powers Property to write the expression as a power of 2. 2^(30)/2^(21) &= 2^(30- 21) &= 2^9 We would need 2^9 floppy disks with 2^(21) bytes of memory to store just 1 gigabyte of information! In other words, we would need 512 floppy disks! We have much better storage devices these days that can hold many gigabytes worth of information, so floppy disks have now fallen out of use.
Divide the monomials.
Let's take a look at the given expression. x^6y^3/x^2y We can begin by writing the expression as a product of two divisions. One factor will have the variable x and the other factor the variable y. x^6y^3/x^2y = x^6/x^2 * y^3/y Remember that if no power is written on a variable, the power is assumed to be 1. x^6y^3/x^2y = x^6/x^2 * y^3/y^1 We can now use the Quotient of Powers Property to divide the resulting monomials. Do this by subtracting the power of the denominator from the power of the numerator.
Finally, finish by multiplying the monomials. x^6y^3/x^2y = x^4y^2
Let's take a look at the next expression.
p^7q^5/p^2q^4
Let's follow the same steps we did in Part A. We will first write this expression as a product of two divisions. One factor will have the variable p and the other factor the variable q.
p^7q^5/p^2q^4 = p^7/p^2 * q^5/q^4
We can now use the Quotient of Powers Property to divide each of the resulting monomials.
Recall that any number raised to the power of 1 is equal to itself. p^7q^5/p^2q^4 &= p^5 * q^1 &= p^5 * q Finally, multiply the monomials. p^7q^5/p^2q^4 = p^5q