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ZX=38
Let's analyze the given quadrilateral WXYZ to find the length ZX. We are told that the figure is a rectangle.
First, by the Segment Addition Postulate, we can express the length of each diagonal as the sum of lengths of its smaller segments.
ZX= ZP+PX and WY=WP+PY
| Equation | ZX=ZP+PX | WY=WP+PY |
|---|---|---|
| Substitution | ZX=ZP+ ZP | WY= PY+PY |
| Simplification | ZX=2ZP | WY=2PY |
| Substitution | ZX=2( 4x-9) | WY=2( 2x+5) |
Now, recall that the diagonals of a rectangle are congruent. Therefore, their lengths are equal. ZX=WY ⇔ 2(4x-9)=2(2x+5) We can use this equation to solve for x.
Now that we know the value of x, we can find ZX using the equation from the table.
We found that the length of ZX is 38.