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Think of the sides as transversals to two other sides of the quadrilateral.
See solution.
We are asked to show that a quadrilateral with four right angles is a rectangle. Let's look at two consecutive right angles at a time.
Let's focus on the other two parallel sides now.
Segments AD and BC are both perpendicular to AB, so they are also parallel. AD≅BC Since both pairs of opposite sides of quadrilateral ABCD are parallel, it is a parallelogram. By definition, a parallelogram with four right angles is a rectangle, so ABCD is a rectangle.
Let's summarize the steps above in a paragraph proof as asked.
2 &Given:&& ∠ A, ∠ B, ∠ C, and∠ D are right angles &Prove:&& ABCD is a rectangle Proof: Since AB and DC are both perpendicular to AD, according to the Perpendicular Transversal Converse Theorem, AB∥DC. Similarly, AD∥BC, since AD and BC are both perpendicular to AB. Quadrilateral ABCD has two pairs of parallel sides, so by definition it is a parallelogram. Quadrilateral ABCD is a parallelogram with four right angles, so by definition it is a rectangle