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Use the Isosceles Triangle Theorem to find a pair of congruent angles. Also, remember that all the angles of an equilateral triangle are congruent. Use the definition of supplementary angles.
See solution.
Since △ HJM is isosceles, we have that JH ≅ MH and, by the Isosceles Triangle Theorem, we have that ∠ J ≅ ∠ M. Additionally, since △ HKL is equilateral, all its angles measure 60^(∘).
By substituting m ∠ HKL=60^(∘) = m ∠ HLK, we obtain an important relation. m∠ JKH + 60^(∘) = 180^(∘) & ⇒ m∠ JKH = 120^(∘) 60^(∘) + m∠ MLH = 180^(∘) & ⇒ m∠ MLH = 120^(∘) From the above, we get that ∠ JKH ≅ ∠ MLH.
Let's list the congruent parts between △ HJK and △ HML. cc ∠ HKJ ≅ ∠ HLM & Angle ∠ J ≅ ∠ M & Angle JH ≅ MH & Non-included Side By the Angle-Angle-Side (AAS) Congruence Postulate we obtain that △ HKJ ≅ △ HLM, which implies that ∠ JHK ≅ ∠ MHL.
Given: & △ HJM is isosceles & △ HKL is equilateral & ∠ JKH and ∠ HKL are supplementary & ∠ HLK and ∠ MLH are supplementary Prove: & ∠ JHK ≅ ∠ MHL Proof: Since △ HJM is isosceles then JH≅ MH, and by the Isosceles Triangle Theorem we have that ∠ J ≅ ∠ M. We also have that △ HKL is equilateral, which means that ∠ HKL ≅ ∠ HLK. Additionally, we are told that ∠ HKL and ∠ HKJ, and ∠ HLK and ∠ HLM, are supplementary angles.
By the Congruent Supplements Theorem we conclude that ∠ HKJ ≅ ∠ HLM. Consequently, by the Angle-Angle-Side (AAS) Congruence Postulate we obtain that △ HKJ ≅ △ HLM and so, ∠ JHK ≅ ∠ MHL.