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Statements
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Reasons
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1. QR ⊥ QT, ST ⊥ QT, QT∥ SR, △ VSR is isosceles with base SR, and QT∥ SR
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1. Given
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2. ∠RQV and ∠STV are right angles
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2. Definition of perpendicular lines
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3. ∠RQV ≅ ∠STV
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3. All the right angles are congruent
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4. VR ≅ VS
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4. Definition of isosceles
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5. ∠VSR ≅ ∠VRS
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5. Isosceles Triangle Theorem
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6. ∠QVR ≅ ∠VRS and ∠TVS ≅ ∠VSR
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6. Alternate Interior Angle Theorem
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7. ∠QVR ≅ ∠TVS
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7. Transitive Property of Congruence
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8. △ RQV ≅ △ STV
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8. Angle-Angle-Side Theorem
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We will prove that △ RQV ≅ △ STV. Therefore, we will construct a two column proof. In our first step, we will state the given statements and the statement that we will prove.
Given: QR ⊥ QT, ST ⊥ QT, QT∥ SR, and △ VSR is isosceles with base SR, and QT∥ SR
Prove: △ RQV ≅ △ STV
Using the given statements QR ⊥ QT and ST ⊥ QT, we can write the second step of the proof.
5. Isosceles Triangle Theorem ∠VSR ≅ ∠VRS Because QT≅ RS, the sixth step of the proof can be written by the Alternate Interior Angle Theorem.
6. Alternate Interior Angle Theorem ∠QVR ≅ ∠VRS and ∠TVS ≅ ∠VSR By the Transitive Property of Congruence and fourth step, we can write the seventh step. 7. Transitive Property of Congruence ∠QVR ≅ ∠TVS As a result, two angles and the nonincluded side of △ RQV are congruent to the corresponding two angles and side of △ RQV. Thus, we can complete our proof by Angle-Angle-Side Theorem. 8. Angle-Angle-Side Theorem △ RQV ≅ △ STV Using these steps, let's construct the two column proof.
Statements
|
Reasons
|
1. QR ⊥ QT, ST ⊥ QT, QT∥ SR, △ VSR is isosceles with base SR, and QT∥ SR
|
1. Given
|
2. ∠RQV and ∠STV are right angles
|
2. Definition of perpendicular lines
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3. ∠RQV ≅ ∠STV
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3. All the right angles are congruent
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4. VR ≅ VS
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4. Definition of isosceles
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5. ∠VSR ≅ ∠VRS
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5. Isosceles Triangle Theorem
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6. ∠QVR ≅ ∠VRS and ∠TVS ≅ ∠VSR
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6. Alternate Interior Angle Theorem
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7. ∠QVR ≅ ∠TVS
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7. Transitive Property of Congruence
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8. △ RQV ≅ △ STV
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8. Angle-Angle-Side Theorem
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To find the distance between QR and ST which is QT, we will use the Pythagorean Theorem in â–³ RQV to find QV.
VR= 2.5, QR= 2
Calculate power
LHS-4=RHS-4
sqrt(LHS)=sqrt(RHS)
Rearrange equation
Because congruent parts of congruent triangles are congruent, we can state that VT=1.5 meters. Now we can use the Segment Addition Postulate. QV+VT=QT Using this equation, let's find QT.
Substitute values
Add terms
Rearrange equation
As a result, the distance between QR and ST is 3 meters.