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If AE and BD bisect each other at point C, then BC ≅ CD and AC≅ CE.
F
Using the fact that AE and BD bisect each other at point C, we can conclude that BC ≅ CD and AC≅ CE.
We can also see that ∠BCA and ∠DCE are vertical angles. Therefore, m∠BCA≅ m∠DCE by the Vertical Angles Theorem.
Two sides and the included angle of △ BCA are congruent to two sides and the included angle of △ DCE. Thus, △ BCA≅ △ DCE by the Side-Angle-Side Theorem. To prove that DE ≅ DC, we need to prove that ∠E ≅ ∠DCE. Once we know this, DE ≅ DC because △ DCE is isosceles and the corresponding angles are congruent.
Because corresponding parts of corresponding triangles are congruent, If ∠A ≅ ∠BCA, then ∠E ≅ ∠DCE. Therefore, the additional statement ∠A ≅ ∠BCA is required. The correct choice is F.