Sign In
If two angles and a non-included side of a triangle are congruent to two angles and the corresponding non-included side of another triangle, then the triangles are congruent.
Based on the diagram above, the theorem can be written as follows.
∠A ≅ ∠D ∠B ≅ ∠E BC ≅ EF ⇒ △ ABC ≅ △ DEF
The primary purpose of the proof is finding a rigid motion or sequence of rigid motions that maps one triangle onto the other. This can be done in several ways. One of the ways will be shown here.
Since the image of the translation does not match △ ABC, at least one more transformation is needed.
As before, the image does not match △ ABC. Therefore, a third rigid motion is required.
Reflect △ CBD'' across BC. Because reflections preserve angles, BD'' and CD'' are mapped onto BA and CA, respectively. Then, the point of intersection of the original segments D'' is mapped onto the point of intersection of the image segments A.
This time the image matches △ ABC.
Consequently, after a sequence of rigid motions, △ DEF can be mapped onto △ ABC. This means that △ DEF and △ ABC are congruent triangles. The proof is complete.