McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Isosceles and Equilateral Triangles
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Exercise 63 Page 382

Use the definition of supplementary angles.

Statements
Reasons
1.
∠ ACB ≅ ∠ ABC
1.
Given
2.
m∠ ACB = m∠ ABC
2.
Definition of Congruent Polygons
3.
∠ ACB and ∠ XCA, and ∠ ABC and ∠ YBA, are supplementary angles
3.
From the diagram
4.
m∠ ACB + m∠ XCA = 180^(∘) and m∠ ABC + m∠ YBA = 180^(∘)
4.
Definition of Supplementary Angles
5.
m∠ ABC + m∠ XCA = 180^(∘) and m∠ ABC + m∠ YBA = 180^(∘)
5.
Substitution
6.
m∠ XCA - m∠ YBA = 0
6.
Subtracting equations
7.
m∠ XCA = m∠ YBA
7.
Solving equation for m∠ XCA
8.
∠ XCA ≅ ∠ YBA
8.
Definition of Congruent Angles
Practice makes perfect

Let's mark the congruent angles in the given diagram.

We have that ∠ XCA and ∠ ACB are supplementary, and also that ∠ YBA and ∠ ABC. By the definition of supplementary angles, we get two important equations. m∠ XCA + m ∠ ACB &= 180^(∘) m∠ YBA + m ∠ ABC &= 180^(∘) Since ∠ ACB ≅ ∠ ABC, we have that m ∠ ACB = m ∠ ABC. m∠ XCA + m ∠ ABC &= 180^(∘) m∠ YBA + m ∠ ABC &= 180^(∘) Next, we subtract the second equation from the first one. m∠ XCA + m ∠ ABC &= 180^(∘) ^- m∠ YBA + m ∠ ABC &= 180^(∘) m∠ XCA - m∠ YBA &= 0 The latter equation tells us that m∠ XCA = m∠ YBA and so, ∠ XCA ≅ ∠ YBA.

We will summarize the proof in the following two-column table.

Statements
Reasons
1.
∠ ACB ≅ ∠ ABC
1.
Given
2.
m∠ ACB = m∠ ABC
2.
Definition of Congruent Polygons
3.
∠ ACB and ∠ XCA, and ∠ ABC and ∠ YBA, are supplementary angles
3.
From the diagram
4.
m∠ ACB + m∠ XCA = 180^(∘) and m∠ ABC + m∠ YBA = 180^(∘)
4.
Definition of Supplementary Angles
5.
m∠ ABC + m∠ XCA = 180^(∘) and m∠ ABC + m∠ YBA = 180^(∘)
5.
Substitution
6.
m∠ XCA - m∠ YBA = 0
6.
Subtracting equations
7.
m∠ XCA = m∠ YBA
7.
Solving equation for m∠ XCA
8.
∠ XCA ≅ ∠ YBA
8.
Definition of Congruent Angles