McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Angles of Elevation and Depression
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Exercise 14 Page 666

Sketch a diagram describing the given situation. Then recall the definition of tangent.

Plum Island Lighthouse.

Practice makes perfect

We are given that Little Gull Island Lighthouse shines a light from a height of 91 feet with a 6^(∘) angle of depression and that the Plum Island Lighthouse, which is located 1800 feet from the first one, shines a light from a height of 34 feet with a 2^(∘) angle of depression. Let's sketch a diagram describing this situation.

First, let's recall that the angle of depression and the angle of elevation are congruent by the Alternate Interior Angles Theorem.

We are asked to determine which of the lighthouses shines a light that reach a boat that sits exactly between them. Let x and y represent the range of lights of Little Gull Island and Plum Island.

To find the values of x and y, we can use one of the trigonometric ratios. Let's recall that the tangent of ∠ A is the ratio of the leg opposite ∠ A to the leg adjacent ∠ A. Using this definition, we can create equations for tan 6^(∘) and tan 2^(∘). tan 6^(∘)=91/x tan 2^(∘)=34/y Let's solve the above equations. We will start with the first one.
tan6^(∘)=91/x
xtan6^(∘)=91
x=91/tan6^(∘)
x=865.807...
x≈865.8
Next we will solve for y in the same way.
tan2^(∘)=34/y
ytan2^(∘)=34
y=34/tan2^(∘)
y=973.632...
y≈973.6
Let's add this information to our picture.

We know that the boat is exactly between the lighthouses, so it lies 18002=900 feet from each of the lighthouses. Let's compare this distance to the range of light of each lightouse. 865.8 < 900 973.6>900 Since Plum Island Lighthouse's light has a range that is greater than 900, it will reach the boat. However, as the Little Gull Island's light has a range that is less than the distance to the boat, the light will not reach a boat.