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Use the Triangle Proportionality Theorem and look for alternate angles and corresponding angles.
Statements
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Reasons
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1. CD bisects ∠ACB and AE∥ CD by construction
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1. Given
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2. AD/DB = EC/BC
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2. Triangle Proportionality Theorem
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3. ∠1 ≅ ∠3
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3. Alternate Interior Angles Theorem
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4. ∠2 ≅ ∠E
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4. Corresponding Angles Postulate
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5. ∠1 ≅ ∠2
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5. Definition of angle bisector
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6. ∠3 ≅ ∠E
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6. Transitive Property of Congruence
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7. EC ≅ AC
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7. Converse Isosceles Triangle Theorem
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8. EC = AC
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8. Definition of congruent segments
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9. AD/DB = AC/BC
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9. Substitution
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Let's begin by marking the parallel segments in the given diagram.
By the Triangle Proportionality Theorem, we obtain the relation below.
Additionally, ∠1 ≅ ∠2 by definition of angle bisector. Consequently, we have that ∠3 ≅ ∠E. Thus, by the Converse Isosceles Triangle Theorem, we get that EC ≅ AC.
By definition of congruent segments, we have that EC = AC. Finally, let's substitute it into the initial equation. AD/DB = AC/BC
Let's summarize the proof we just did in the following table.
Statements
|
Reasons
|
1. CD bisects ∠ACB and AE∥ CD by construction
|
1. Given
|
2. AD/DB = EC/BC
|
2. Triangle Proportionality Theorem
|
3. ∠1 ≅ ∠3
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3. Alternate Interior Angles Theorem
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4. ∠2 ≅ ∠E
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4. Corresponding Angles Postulate
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5. ∠1 ≅ ∠2
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5. Definition of angle bisector
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6. ∠3 ≅ ∠E
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6. Transitive Property of Congruence
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7. EC ≅ AC
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7. Converse Isosceles Triangle Theorem
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8. EC = AC
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8. Definition of congruent segments
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9. AD/DB = AC/BC
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9. Substitution
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Since CD is the bisector of ∠ACB, we can apply the Triangle Angle Bisector (Theorem 7.11) and get the required relation directly. AD/DB = AC/BC