Sign In
Use the Triangle Proportionality Theorem and look for alternate angles and corresponding angles.
Statements
|
Reasons
|
1. CD bisects ∠ ACB and AE∥ CD by construction
|
1. Given
|
2. AD/DB = EC/BC
|
2. Triangle Proportionality Theorem
|
3. ∠ 1 ≅ ∠ 3
|
3. Alternate Interior Angles Theorem
|
4. ∠ 2 ≅ ∠ E
|
4. Corresponding Angles Postulate
|
5. ∠ 1 ≅ ∠ 2
|
5. Definition of angle bisector
|
6. ∠ 3 ≅ ∠ E
|
6. Transitive Property of Congruence
|
7. EC ≅ AC
|
7. Converse Isosceles Triangle Theorem
|
8. EC = AC
|
8. Definition of congruent segments
|
9. AD/DB = AC/BC
|
9. Substitution
|
Let's begin by marking the parallel segments in the given diagram.
AD/DB = EC/BC By applying the Alternate Interior Angles Theorem and the Corresponding Angles Postulate, we have that ∠ 1 ≅ ∠ 3 and ∠ 2 ≅ ∠ E respectively.
Additionally, ∠ 1 ≅ ∠ 2 by definition of angle bisector. Consequently, we have that ∠ 3 ≅ ∠ E. Thus, by the Converse Isosceles Triangle Theorem, we get that EC ≅ AC.
By definition of congruent segments, we have that EC = AC. Finally, let's substitute it into the initial equation. AD/DB = AC/BC
Let's summarize the proof we just did in the following table.
Statements
|
Reasons
|
1. CD bisects ∠ ACB and AE∥ CD by construction
|
1. Given
|
2. AD/DB = EC/BC
|
2. Triangle Proportionality Theorem
|
3. ∠ 1 ≅ ∠ 3
|
3. Alternate Interior Angles Theorem
|
4. ∠ 2 ≅ ∠ E
|
4. Corresponding Angles Postulate
|
5. ∠ 1 ≅ ∠ 2
|
5. Definition of angle bisector
|
6. ∠ 3 ≅ ∠ E
|
6. Transitive Property of Congruence
|
7. EC ≅ AC
|
7. Converse Isosceles Triangle Theorem
|
8. EC = AC
|
8. Definition of congruent segments
|
9. AD/DB = AC/BC
|
9. Substitution
|
We begin by highlighting the congruent angles in the given diagram.
Since CD is the bisector of ∠ ACB, we can apply the Triangle Angle Bisector (Theorem 7.11) and get the required relation directly. AD/DB = AC/BC