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Recall the definition of the tangent.
≈ 154.9 ft
We are given that a digital camera with a panoramic lens is described as having a view with an angle of elevation of 38^(∘), and this camera is on a 3-foot tripod aimed directly at a 124-foot tall monument. Let's begin with sketching a diagram describing the given situation, and we will name the vertices.
First, let's evaluate the length of BC.
To evaluate the value of x, we can use one of the trigonometric ratios. Let's recall that the tangent of ∠A is the ratio of the leg opposite ∠A to the leg adjacent ∠A. Using this definition, we can create an equation for tan 38^(∘). tan 38^(∘)=121/x Let's solve the above equation.
LHS * x=RHS* x
.LHS /tan38^(∘).=.RHS /tan38^(∘).
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Round to 1 decimal place(s)
We should place the tripod approximately 154.9 feet away from the monument.