McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Angles of Elevation and Depression
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Exercise 12 Page 666

Sketch a diagram describing the given situation, and then recall the definition of sine.

≈ 23.3 km

Practice makes perfect

We are given that a volcano has a magma reservoir located 15 kilometers beneath the bay, and we're asked to evaluate the length of a magma channel below the sea, which we will call l. We also know that the angle of elevation of a magma channel to the volcano is 40^(∘). Let's sketch a diagram for this situation.

Since the figure is a right triangle, we can use one of the trigonometric ratios to evaluate the value of l. Let's recall that the sine of ∠ A is the ratio of the leg opposite ∠ A to the hypotenuse. Using this definition, we can create an equation for sin 40^(∘). sin 40^(∘)=15/l Let's solve the above equation.
sin 40^(∘)=15/l
lsin 40^(∘)=15
l=15/sin40^(∘)
l=23.3358...
l≈ 23.3
The length of magma channel is approximately 23.3 kilometers.