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With an extended ratio you can express the lengths of the sides with respect to the factor x. You will need one of the trigonometric ratios to find the measure of the angle.
B
An extended ratio compares three or more numbers. In an extended ratio a : b : c, the ratio of the first two numbers is a : b, the ratio of the last two numbers is b : c, and the ratio of the first and last numbers is a : c. We want to find the measure of the smallest angle of a triangle, whose sides fit the given extended ratio. 5 : 12 : 13 This means that we can express the lengths of the sides of the triangle as 5x, 12x, and 13x.
Knowing that, we can determine whether our triangle is acute, right, or obtuse. To do so, we will compare the square of the largest side length to the sum of the squares of the other two side lengths. Let a, b, and c be the lengths of the sides, with c being the longest.
| Condition | Type of Triangle |
|---|---|
| a^2+b^2 < c^2 | Obtuse triangle |
| a^2+b^2 = c^2 | Right triangle |
| a^2+b^2 > c^2 | Acute triangle |
(a b)^m=a^m b^m
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The smallest angle is opposite the shortest side of the triangle. Therefore, we want to find the measure of the angle that is opposite the leg with side length of 5x. Let's call this measure y.
opposite= 5x, adjacent= 12x
a/b=.a /x./.b /x.
Degreeinstead of
Radianin the third row, and push ENTER. Next, we push 2ND followed by TAN, introduce the value 512, and press ENTER.
The angle is about 22.62, which corresponds to option B.