Sign In
Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
Roots: x=5, x=- 2
Number and Type of Roots: two real roots
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0
⇕
x=- b± sqrt(b^2-4 a c)/2 a
We first need to identify the values of a, b, and c.
Substitute values
- (- a)=a
Calculate power
Identity Property of Multiplication
- a(- b)=a* b
Add terms
Calculate root
The roots of the given equation are x= 3± 72. Let's separate them into the positive and negative cases.
| x=3± 7/2 | |
|---|---|
| x_1=3+7/2 | x_2=3-7/2 |
| x_1=10/2 | x_2=- 4/2 |
| x_1=5 | x_2=- 2 |
Using the Quadratic Formula, we found that the roots of the given equation are x=5 and x=- 2, both of which are real.