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4. Equations
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Chapter 5
4. 

Equations

This lesson delves into the complexities of equations, emphasizing the importance of variables, solutions to an equation, and mathematical modeling. It aims to simplify these mathematical tools by connecting them to real-life situations. For instance, equations can be used to calculate costs in group activities or to determine physical characteristics like height and weight. By making these connections, the guide helps both students and professionals understand how to apply equations in practical, everyday contexts.

Student Learning Objectives:
  • Solve simple equations
  • Translate written expressions into equations
  • Determine whether a given value is a solution to an equation
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10 Theory slides
8 Exercises - Grade E - A
Each lesson is meant to take 1-2 classroom sessions
Equations
Slide of 10
Problems or situations in daily life can often be represented by algebraic expressions. When an expression is set equal to another expression or number, it is called an equation. This lesson introduce equations and how to use them to model real-life situations.

Catch-Up and Review

Here are a few recommended readings before getting started with this lesson.

Challenge

Finding the Correct Floor

Tadeo and his little brother Dylan are in an elevator. Dylan randomly presses buttons on the panel.

The elevator goes 3 floors up and then 7 floors down before arriving at the ground floor, or Floor 1. Which floor were Tadeo and his brother on when they got on the elevator?

Discussion

Equation

An equation is a type of mathematical relation that indicates that shows that two quantities are equal. Equations often contain one or more unknown values called variables.

equations with one and two variables
Solving an equation with a variable means to find the value or values of each variable that make the equation true.
Discussion

Solution of an Equation

A solution of an equation is a value that makes the equation true. It satisfies the equation when it is substituted for the variable of the equation. Consider the following equation. x+1=4 The solution of the equation is x=3 because 3 is the only value of x that makes the equation true.

x+1=4
3+1? = 4
4=4 ✓
For the other values that are not solutions, the right-hand side of the solution is not equal to the left-hand side. This is shown by a not equal sign ≠. Consider the result of substituting x=1 into the equation.
x+1=4
1+1 ? = 4
2≠ 4 *
Some equations are have no solution. For example, x=x+1 can never be true because a number cannot equal more than one of itself. x=x+1 * Equations can have multiple or even infinitely many solutions. x+x=2x

This equation will be true for all values of x since the expressions on the left- and right-hand sides are equivalent expressions.
Example

Deciding What to Order

A restaurant has four different combos meals.

a

Suppose two customers order the same combo. The price of their combo satisfies the equation 2x+8=22. Which combo did they choose?

b

Now suppose they order different combos. The prices of the combos they choose satisfy the equation x^2-15x=-54. Select the combos they chose.

Hint

a

Substitute the given prices into the equation. Which combo makes the equation true?

b

Substitute the given prices into the equation. Which combos make the equation true?

Solution

a

To find which combo the two customers chose, we substitute each combo price into the equation and check whether it satisfies the equation. Let's start with the price of Combo I, which is $ 7.

2x+8=22
2( 7)+8 ? =22
14+8? =22
22=22 ✓

Since x=7 makes the equation true, it is a solution to the equation. Next, we substitute the remaining combo prices and simplify to check whether the equation has any other solutions.

Menu Menu Price ($)  Substitution into 2x+8=22 Check
Combo I 7 2( 7)+8? =22 22 = 22   ✓
Combo II 9 2( 9)+8? =22 26 ≠ 22   *
Combo III 5 2( 5)+8? =22 18 ≠ 22   *
Combo IV 6 2( 6)+8? =22 20 ≠ 22   *

Only the price of Combo I satisfies the equation, so they ordered Combo I.

b

To find which combos they chose, we use the same method as in Part A. We substitute each combo price into the equation and check whether it satisfies the equation. Let's start with the price of Combo I.

x^2-54x=15
( 7)^2-15( 7) ? =-54
49-15(7)? =-54
49-105? =-54
-56 ≠ -54

Since x=7 does not satisfy the given equation, it is not a solution. Neither customer ordered Combo I. Next, we check the remaining combo prices.

Menu Menu Price  Substitution into x^2-15x=-54 Check
Combo I 7 ( 7)^2-15( 7)? =-54 49-105? =-54 -56 ≠ -54   *
Combo II 9 ( 9)^2-15( 9)? =-54 81-135 ? =-54 -54 = -54   ✓
Combo III 5 ( 5)^2-15( 5)? =-54 25-75 ? =-54 -50 ≠ -54   *
Combo IV 6 ( 6)^2-15( 6)? =-54 36-90 ? =-54 -54 = -54   ✓

We found that x = 9 and x = 6 are solutions to the equation. Since they ordered different combos, one customer ordered Combo II, and the other ordered Combo IV.

Pop Quiz

Checking Solutions

Determine whether the value is a solution to the equation.

Number and the Equation
Example

Writing Equations

Write an equation for each situation.

a

A bookshelf is 12 centimeters taller than a cabinet. The bookshelf is 168 centimeters tall. Write an equation to find the height of the cabinet.

b

A smaller box weighs three-fourths as much as the larger box. The larger box weighs 52 kilograms. Write an equation to find the weight of the smaller box.

c

The difference between the ages of an oak tree and a maple tree is 3 years. The oak tree is older and is 16 years old. Write an equation to find the age of the maple tree.

Hint

a

The bookshelf is 12 centimeters taller than the cabinet. This involves adding some numbers.

b

Three-fourths of a number is the same as the product of 34 and that number.

c

Difference indicates subtraction.

Solution

a

To write the equation for the situation, let's start by writing it in words. Then, we can look at smaller phrases and write them as algebraic expressions.

The word is represents an equals sign, which means that the expressions to the left and right of this word are equal. We also know that the bookshelf's height is 168 centimeters.

Next, more than stands for addition. We can also use a variable x to represent the height of the cabinet.

Saying that the height of the cabinet is 12 centimeters less than the bookshelf's height is another way of saying the same thing. Here, less than stands for subtraction. x=168-12 Both equations can be used to find the height of the cabinet.

b

Three-fourths of a number means the product of 34 and that number. With this in mind, let's write the sentence as an equation using x for the weight of the smaller box.

We can also write the fraction 34 as 75100 or 0.75. This means that, for example, the equation x=0.75 * 52 also represents the given sentence.

c

Here, the word difference stands for subtraction. Let's use x for the age of the maple tree and translate the words into an equation.

Another way to state the situation is to say that the oak tree is 3 years older than the maple tree. Then, its age is the maple tree's age plus 3. x+3=16 Both equations can be used to find the age of the maple tree. A situation can be represented by more than one equation. We can rewrite an equation in different ways by rearranging its terms.

Example

Buying Games

Dylan and Tadeo visit a game store.

Pokemoncards.jpg

a

Dylan purchases 7 new premium trading cards. After this purchase, he has 25 premium cards. How many premium cards did Dylan have before he bought the new ones?

b

After buying 3 used games for $ 15, Tadeo is left with $ 32 in his wallet. How much money did he have before he bought the games?

Hint

a

The number of cards Dylan had before going into the store is 7 less than 25.

b

Tadeo started with $15 more than the $32 he has left after buying the games.

Solution

a

Dylan bought 7 new cards and now has 25 in total. This means he had 7 fewer cards before buying more. Let n represent the number of cards he had before buying more, and write an equation to find n.

n= 25- 7 Now we simplify the equation to find how many cards he had.

n=25-7
n=18

The solution to the equation is n=18. This means that Dylan had 18 premium cards before buying more.

b

The amount of money Tadeo started with is the total of the $ 15 he spent on the games and the $ 32 he had left after the purchase. Let's use m to represent the amount of money he started with and write an equation for this situation.

m= 32+ 15 Now we can simplify the equation.

m=32+15
m=47

We found that Tadeo had $ 47 before buying the games.

Example

Selling Old Toys

Mark and Kevin are selling their old toy cars at a secondhand store.

Oldcartoys.jpg

a

The store pays them $ 36 for 12 cars. If each car is worth the same amount, how much do they get for one car?

b

How many cars do the boys need to sell to earn $54?

Hint

a

To find the amount paid for one car, divide $36 by 12.

b

Use the amount from Part A. Write a division equation to represent the situation.

Solution

a

The store paid the boys the same amount for each toy car. This means we can find x, the amount they got for one car, by dividing the total of $ 36 they received by the 12 cars they sold.

x = 36/12 ⇒ x= 3 The solution to the equation is x=3, so the shop paid the boys $ 3 for each toy car sold.

b

In Part A, we found that the store pays $ 3 for each car. To find the number of cars, y, they need to sell to get $ 54, we divide 54 by 3.

y = 54/3 ⇒ y = 18 The boys need to sell 18 toy cars.

Closure

Finding the Correct Floor

At the beginning of the lesson, Dylan randomly pressed some elevator buttons.

The elevator went 3 floors up and then 7 floors down before arriving at the ground floor, or Floor 1. Which floor were Tadeo and his brother on when they got on the elevator?

Hint

Try to undo their trip.

Solution

Let's think about this problem backwards. We can use a variable x for the floor where the boys got into the elevator.

After going 3 floors up and then 7 floors down, they ended up on Floor 1. If we reverse their trip, they go 7 floors up from Floor 1 and then 3 floors down, arriving at Floor x. We can use this information to write an equation. x = 1 + 7 - 3 Now we can simplify this equation to find the floor the boys were on when they got on the elevator.

x = 1 + 7 - 3
x = 8 - 3
x = 5

The solution to the equation is x=5. This means that the boys got on the elevator on Floor 5.



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