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Core Connections Integrated II, 2015

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Core Connections Integrated II, 2015 View details

1. Section 7.1

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Exercise 63 Page 395

Practice makes perfect

a To calculate the probability of two events happening, we have to use the Multiplication Rule of Probability.

P(A and B)=P(A)* P(B) Since the same coin is flipped, the probability of both events is 0.7. With this, we can calculate the probability that Earl will do both chores.

P(A and B)=P(A)* P(B)

SubstituteValues

Substitute values

P(both)= 0.7* 0.7

Multiply

P(both)=0.49

Convert to percent

P(both)=49 %

b Let's illustrate the different outcomes with a tree diagram. We will assume that the first coin toss decides whether or not Earl has to take out the garbage and the second if he needs to do the dishes. The highlighted path shows the outcome that results in garbage duty but no need to wash the dishes.

Again, to calculate the probability of this event, we have to use the Multiplication Rule of Probability.

P(A and B)=P(A)* P(B)

P(A)= 0.7, P(B)= 0.3

P(garbage, no dishes)=( 0.7)( 0.3)

Multiply

P(garbage, no dishes)=0.21

Convert to percent

P(garbage,no dishes)=21 %

There is a 21 % probability that Earl will not have to take out the garbage but will have to do the dishes.

Subchapter links

7.1.1 Explore–Conjecture–Prove p.376-379

7.1.2 Properties of Rhombi p.382-383

7.1.3 Two-Column Proofs p.387-388

7.1.4 More Geometric Proofs p.390-391

7.1.5 Using Similar Triangles to Prove Theorems p.395-396