Core Connections Integrated II, 2015
CC
Core Connections Integrated II, 2015 View details
1. Section 7.1
Continue to next subchapter

Exercise 43 Page 388

Practice makes perfect
a To solve the given exponential equation, we will start by rewriting the terms so that they have a common base.
16^(3/4)=4^x
(4^2)^(3/4) = 4^x
4^(2(3/4)) = 4^x
4^(6/4)=4^x
4^(3/2)=4^x
Now we have two equivalent expressions with the same base. If both sides of the equation are equal, the exponents must also be equal. 4^(3/2)=4^x ⇔ 3/2 = x Therefore, x= 32 is the solution to our equation.
b To solve the given exponential equation, we will start by rewriting the terms so that they have a common base.
8^(1/3)=4^x
(2^3)^(1/3)=(2^2)^x
2^(3(1/3))=2^(2x)
2^1=2^(2x)
Now we have two equivalent expressions with the same base. If both sides of the equation are equal, the exponents must also be equal. 2^1=2^2x ⇔ 1=2x Finally, we will solve the equation 1=2x.
1=2x
1/2=x
x=1/2
c To solve the given exponential equation, we will start by rewriting the terms so that they have a common base.
3^(4x) = 9^2
3^(4x) = ( 3^2 )^2
3^(4x) = 3^(2(2))
3^(4x) = 3^4
Now we have two equivalent expressions with the same base. If both sides of the equation are equal, the exponents must also be equal. 3^(4x) = 3^4 ⇔ 4x = 4 Finally, we will solve the equation 4x = 4.
4x = 4
x=1
d To solve the given exponential equation, we will start by rewriting the terms so that they have a common base.
(1/2)^x=4
(2^0/2^1)^x=2^2
(2^(0-1))^x=2^2
(2^(-1))^x=2^2
2^(- x) = 2^2
Now we have two equivalent expressions with the same base. If both sides of the equation are equal, the exponents must also be equal. 2^(- x) = 2^2 ⇔ - x = 2 Finally, we will solve the equation - x = 2.
- x = 2
x=-2