Exercise 41 Page 387

If we illustrate this situation, we get a right triangle where the hypotenuse and the opposite side to the angle we want to determine are known. If we label the angle the cable makes with the ground θ, we can use the sine ratio to write an equation.

Let's solve this equation.

sin θ =70/100

sin^(-1)(LHS) = sin^(-1)(RHS)

θ =sin^(- 1)70/100

UseCalc

Use a calculator

θ =44.42700...^(∘)

RoundDec

Round to 2 decimal place(s)

θ ≈ 44.43^(∘)

The angle is about 44.43^(∘), which corresponds to option B.