Start by splitting the last intervals into two intervals of the same size.
Example Answer:
Practice makes perfect
Consider the given histogram. We will redraw it to make it not misleading.
Note that the third interval is actually covering two intervals, 60-89 and 90-119. Additionally, the frequency of 60-119 is about 19. Therefore, to correct the graph we can split this frequency to give 60-89 a frequency of 10 and 90-119 a frequency of 9. Finally, let's set the scale on the vertical axis to start at 0. We can now correct the given graph.
Please note that we are only showing one possible solution of the many possible.
