Exercise 26 Page 368

Consider the given histogram. We will redraw it to make it not misleading.

Note that the third interval is actually covering two intervals, $60-89$ and $90-119.$ Additionally, the frequency of $60-119$ is about $19.$ Therefore, to correct the graph we can split this frequency to give $60-89$ a frequency of $10$ and $90-119$ a frequency of $9.$ Finally, let's set the scale on the vertical axis to start at $0.$ We can now correct the given graph.

Please note that we are only showing one possible solution of the many possible.