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| Student Learning Objectives: |
|---|
|
| | 12 Theory slides |
| | 11 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Izabella's favorite candy, Frutty, is sold in packs of thirty candies with three different flavors — apple, orange, and banana.
Izabella wants to know how many banana-flavored candies there are in each pack, so she bought ten packs and counted the number of banana candies in each. Her results are as follows. 10 , 8, 10, 9, 12, 9, 10, 10, 12, 10 Draw a dot plot to represent the data.
The number of dots drawn on the dot plot above a certain number should match the frequency of that number in the data set. 10, 8, 10, 9, 12, 9, 10, 10, 12, 10 Given the data set compare the frequencies of the numbers.
From here, the dot plot can be drawn as follows.
A multiple-choice test has ten questions. After grading the test, the teacher produced the following dot plot to show how many correct answers each student had on the test.
How many students are there in the class?
| Number | Dots Above the Number | Conclusion |
|---|---|---|
| 0,1,2,3 | 0 | There are no students who answered fewer than four questions correctly. |
| 4 | 1 | One student answered four questions correctly. |
| 5 | 3 | Three students answered five questions correctly. |
| 6 | 2 | Two students answered six questions correctly. |
| 7 | 4 | Four students answered seven questions correctly. |
| 8 | 5 | Five students answered eight questions correctly. |
| 9 | 3 | Three students answered nine questions correctly. |
| 10 | 2 | Two students answered all ten questions correctly. |
The number of students in the class is equal to the number of dots in the diagram. 1+3+2+4+5+3+2=20 There are 20 students in the class who took this test.
A college hockey team played 23 games during a season. An enthusiastic fan made a dot plot of the number of goals the team scored in each game.
The following data set shows the ages of the first 45 presidents of the United States when their presidencies began. The president's name and presidential period can be displayed by clicking on and holding down each point.
| Interval | Frequency |
|---|---|
| 40--44 | 2 |
| 45--49 | 7 |
| 50--54 | 12 |
| 55--59 | 13 |
| 60--64 | 8 |
| 65--69 | 2 |
| 70--74 | 1 |
Use these intervals and frequencies to draw the histogram.
In 1936, Sir Ronald Aymler Fisher published a paper entitled The Use of Multiple Measurements in Taxonomic Problems.
Fisher investigated several measurements of three species of flowers.
The histogram below shows the summary of the data about the sepal length of the Iris virginica flowers.
How many Iris Virginica flowers did Fisher investigate in this paper?
The total number of flowers in the experiment is the sum of these counts. 1+0+6+17+14+6+6=50 Fisher investigated the data of about 50 Iris virginica flowers.
A ranger is surveying a forest. He randomly selected 40 loblolly pines (Pinus taeda) and measured their heights. The histogram below is the summary of the data.
The following table shows the test scores of a class of 26 students. 8.5 & 11 & 16 & 12.5 & 11 15.5 & 12 & 7 & 13 & 10.5 5 & 15 & 8 & 9 & 8 8.5 & 6 & 12 & 15 & 15.5 13.5 & 7.5 & 13 & 10.5 & 11.5 13.5 Draw a box plot of the data.
Since there are 26 values, the median is the mean of the numbers at the 13th and 14th positions. 5 & 6 & 7 & 7.5 & 8 8 & 8.5 & 8.5 & 9 & 10.5 10.5 & 11 & 11 & 11.5 & 12 12 & 12.5 & 13 & 13 & 13.5 13.5 & 15 & 15 & 15.5 & 15.5 16 Now, the median can be determined by calculating the average of 11 and 11.5. 11+11.5/2=11.25 The median is 11.25. This is also marked on the number line.
The first quartile is the median of the first half of the data. 5 & 6 & 7 & 7.5 & 8 8 & 8.5 & 8.5 & 9 & 10.5 10.5 & 11 & 11 The third quartile is the median of the second half of the data. & & & 11.5 & 12 12 & 12.5 & 13 & 13 & 13.5 13.5 & 15 & 15 & 15.5 & 15.5 16 The first quartile is 8.5 and the third quartile is 13.5. These are also marked on the number line.
The box-plot is built using these points.
Putting all this together gives the box plot.
In the 1994 report The Population Biology of Abalone (Haliotis species) in Tasmania,
the authors presented and investigated the measurements of 4177 blacklip abalones.
The lengths of the shells in millimeters are summarized in the box plot below.
How many blacklip abalones' lengths were shorter than 90 millimeters in this experiment?
The problem is now to find out how many data points are less than the first quartile. The first quartile is the median of the lower half of the data set. In this experiment there are 4177 data points, so by dividing this by 2, the number of data points in the lower half can be found. 4177/2=2088.5 This means that in the lower half, there are 2088 data points. Now, by dividing 2088 by 2, the placement of the lower quartile can be found. 2088/2=1044 The lower quartile is the average of the 1044th and the 1045th data points. Since the lower quartile is 90, the 1045th data point is not less than 90. Therefore, the number of blacklip abalones that are shorter than 90 millimeters is less than 1045. The only option that meets this condition is 1007.
In fact, there were 60 blacklip abalones with a length of 90 millimeters in the experiment. The answer option 1007 reflects the actual answer to the question, but to get this value, the full data is needed — the box plot is not enough.
The heights, in feet, of red alder (Alnus rubra) trees in a forest are summarized in the following box plot.
In some cases, scientists use visual representations that go beyond the three types of plots discussed in this lesson. For example, the report about the blacklip abalones also contains data about their sex. This can be used to present a summary of the length in a stacked histogram.
Ignacio is a math teacher. On Friday, he gave a pop quiz to each of his classes and plans to give the results to each class on Monday. On Friday night, he wrote the results for each class on different paper slips that look like the following image. He also made dot plots to match each paper slip.
He ran into a huge problem over the weekend — he left the paper slips in his pocket while doing laundry! The box plots are safe, but only the paper slip above still shows the results. That sole surviving paper slip matches one of the following box plots.
Which dot plot matches the results on the paper slip?
To draw the dot plot, we must count the number of times each observation occurs. To make this easier, we can start by arranging the data set in ascending order. 7,7,8,8,8,8,9,9,9,10,10,10,10,11 Now we will count how many times each observation occurs. |c|c| Value & # of Observations 7 & 2 8 & 4 9 & 3 10 & 4 11& 1 The number of observations of a value is represented by the number of dots over that value. For example, over the value 7, there should be 2 dots.
Compare this dot plot to the options. It matches with A.
Consider the following data set. 8,6,0, 1, 5, 3,7,5 1,6,0,6,5,7,0 Which dot plot corresponds to the data set?
To determine which is the correct dot plot, let's draw the one corresponding to the given data. To do so, we will count the number of times that each observation occurs. |c|c| Value & # of observations 0 & 3 1 & 2 3 & 1 5& 3 6& 3 7& 2 8& 1 When we draw the dot plot, we will let the number of observations of a certain value be represented by the number of dots over that value. For example, over the value 0 we place 3 dots.
If we compare this dot plot to the alternatives, we see that it matches with C.
Ignacio's students wrote the lengths of earthworms in centimeters written in ascending order. 4.0,5.2,6.0,7.0,7.1, 8.0,8.2,8.8,9.0,12.0,13.0 Which of the following box plots represents this data set?
To determine which is the correct box plot, let's draw the one corresponding to the given data set. Find the following information. Minimum Value Lower Quartile Median Upper Quartile Maximum Value These values are more clear to find when the set is written in ascending order. Luckily, it already is. Let's begin and determine the median. This is the middle value of the data set.
Since the data set has 11 observations, which is an odd number, the 6^(th) observation must be the median. We will then have an equal number of observations on the left and right sides of the median.
It helps to organize the values in a table. |c|c| [-0.8em] Observation(s) & Data [0.3em] [-0.8em] 1^(st) - 5^(th) & 4.0, 5.2, 6.0, 7.0, 7.1 [0.3em] [-0.8em] Median & 8.0 [0.3em] [-0.8em] 7^(th) - 11^(th) & 8.2, 8.8, 9.0, 12.0, 13.0 [0.3em]
Next, determine the lower and upper quartile by finding the middle observation of the values that are to the left and right of the median. Since the number of observations in each half is odd, the quartiles will be the third and ninth observations, respectively.
Reorganize the table to show the quartiles. This table also shows the minimum and maximum values. |c|c| [-0.8em] Observation(s) & Data [0.3em] [-0.8em] Minimum Value & 4.0 [0.3em] [-0.8em] 2^(nd) & 5.2 [0.3em] [-0.8em] Lower Quartile & 6.0 [0.3em] [-0.8em] 4^(th) and 5^(th) & 7.0, 7.1 [0.3em] [-0.8em] Median & 8.0 [0.3em] [-0.8em] 7^(th) and 8^(th) & 8.2, 8.8 [0.3em] [-0.8em] Upper Quartile & 9.0 [0.3em] [-0.8em] 10^(th) & 12.0 [0.3em] [-0.8em] Maximum Value & 13.0 [0.3em]
Use the values in the table to draw the box plot.
Finally, compare this box plot with the four given ones. The correct option is C.
A chain of restaurants called Wing Wings is known for their tasty chicken wings, of course. It is their secret sauce that makes them both super tasty and have a high calorie count. A dietitian, who wants to bring down the chain, analyzed one wing every day for 31 consecutive days.
Which of the following histograms represents the data collected by the dietitian?
To determine which is the correct histogram, let's draw the one representing the data collected by the dietitian. To do this, first, let's organize the data in a table starting at 120 and with intervals of 20.
| Interval | Observations | Count |
|---|---|---|
| 120-140 | 121.2, 125.7, 126.2, 126.9, 128.2, 135.7, 139.7 |
7 |
| 140-160 | 141.8, 143.0, 143.8, 146.3, 147.4, 147.6, 152.8, 155.2, 156.7, 157.0, 157.0 |
11 |
| 160-180 | 160.5, 163.3, 169.5, 170.7, 170.8, 173.2, 173.5 |
7 |
| 180-200 | 180.1, 181.4, 184.5, 196.1 | 4 |
| 200-220 | 0 | |
| 220-240 | 0 | |
| 240-260 | 0 | |
| 260-280 | 261.0, 275.0 | 2 |
Now that we know the number of observations in each interval, we can draw the histogram.
Comparing this histogram with the given options, the correct choice is B.
Use the box plot to find the required measure.
The least value, or minimum value, of a box plot is given by the end of the left whisker.
As we can see, the minimum value is 1.
The greatest value, or maximum value, is given by the end of the right whisker of the box plot.
The maximum value is 10.
The third quartile in a box plot is marked by the end of the box. The third quartile is also written as Q_3.
As we can see, the third quartile is 5.
The first quartile of a box plot is marked by the start of the box. The first quartile can also be written as Q_1.
The first quartile is 2.
The median of a box plot is given by the vertical line that is found inside of the box.
The median is 4.
The number of classes that Kriz is taking is given by the number of dots in the dot plot. Let's count them.
By adding the number of observations, we can determine how many classes Kriz is taking. 2+3+4+1+1+1=12 Kriz is taking 12 classes.
The greatest number of students is given by the observation we find furthest to the right in the dot plot.
The greatest number of students is 26.
The most common number of students in the classes is the value with the greatest number of observations in the dot plot.
The most common number of students is 22.
To calculate the average number of students per class we must divide the total number of students in all of his classes with the number of classes. Average=Number of students/Number of classes Therefore, we must first add up the number of students.
Now we can calculate the average.
The average number of students per class is 22.