Consider an absolute value inequality.
|k| < 3
The above means that the distance to 0 from k is less than 3.
We see that, for this example, k must be greater than - 3 andless than 3.
|k| < 3 ⇔ k > - 3 and k < 3
Writing the System
Let's apply the same reasoning to the given inequality, where x > 0.
|y| < x ⇔ y > - x and y < x
We can combine the two inequalities that form the above compound inequality to form a system.
y > - x & (I) y < x & (II)
Graphing the System
Let's consider both of these inequalities individually before we combine them to find the solution set for the entire system.
y< x
First, we need to graph the boundary line, which will be dashed because the inequality is strict. Remember that we are also told that x > 0, and must restrict our domain accordingly.
Now we must choose which side of the line to shade. We can choose any arbitrary point within the domain. Let's test the point (1,4). If it produces a true statement, we shade the region which contains the point. Otherwise, we shade the opposite region.
We should shade the side of the line that does not contain this point. Recall, again, that x > 0!
y > - x
Once again, we need to graph our boundary line first. This line is also dashed because we have a strict inequality. Remember that we must restrict our domain according to the fact that x > 0.
Now we must choose which side of the line to shade. We can choose any arbitrary point within the domain to test. Let's test the point (3,-2).
