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The three inequalities we have written so far form a system of linear inequalities. x≥ 8 & (I) x+y≤ 20 & (II) 10x+15y ≥ 120 & (III)
To graph the system, we will consider each inequality separately. Let's start with the easiest, which is Inequality (I). To obtain the boundary line we replace the inequality sign with an equals sign. ccc Inequality & & Boundary Line x ≥ 8 & & x = 8 Note that the boundary line is a vertical line. Moreover, since the inequality is not strict, the line is solid. Since x is greater than or equal to 8, we will shade the half-plane which is to the right of the line. We will only consider the first quadrant, since it is impossible for the number of hours to be negative.
We will follow the same procedure to obtain the information we need to graph Inequality (III).
Inequality | 10x+15y≥ 120 |
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Boundary Line | 10x+15y=120 |
Slope-intercept Form | y=- 2/3x+8 |
Solid or Dashed? | Solid |
Test Point | (0,0) |
True or False Statement? | False * |
Let's graph the third inequality using the above information.
The solution set is the area where all of the inequalities in the system overlap.
We see above that the point (10,8) is a solution to the system. Recall that x is the number of hours we work at the grocery store. Also, y is the number of hours we teach music. Therefore, the solution (10,8) means that we can work 10 hours at the grocery store and teach music lessons for 8 hours.
We see that the point (8,1) is not in the shaded area. Therefore, it is not part of the solution. This means we cannot work 8 hours at the grocery store, teach 1 hour of music lessons, and still make enough money.