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Graph each inequality separately. The solution will be the intersection, or overlap, of the shaded regions.
Graphing a single inequality involves two main steps.
We can tell a lot of information about the boundary lines from the inequalities given in the system.
Let's find each of these key pieces of information for the inequalities in the system. Note that since Inequality (I) is in the form y≥-5, the slope of its boundary line will be equal to 0. This boundary line will be horizontal.
Information | Inequality (I) | Inequality (II) |
---|---|---|
Given Inequality | y≥-5 | y−1<3x |
Boundary Line Equation | y=-5 | y−1=3x |
Solid or Dashed? | ≥ ⇒ Solid | < ⇒ Dashed |
y=mx+b | y=0x+(-5) | y=3x+1 |
Great! With all of this information, we can plot the boundary lines.
Before we can shade the solution set for each inequality, we need to determine on which side of the plane their solution sets lie. To do that, we will need a test point that does not lie on either boundary line.
It looks like the point (0,0) would be a good test point. We will substitute this point for x and y in the given inequalities and simplify. If the substitution creates a true statement, we shade the same region as the test point. Otherwise, we shade the opposite region.
Information | Inequality (I) | Inequality (II) |
---|---|---|
Given Inequality | y≥-5 | y−1<3x |
Substitute (0,0) | (0)≥?-5 | (0)−1<?3(0) |
Simplify | 0≥-5 ✓ | -1<0 ✓ |
Shaded Region | same | same |
For both inequalities, we will shade the region containing our test point. For Inequality (I), it will be above the boundary line, however, for Inequality (II), it will be below.
Finally, to illustrate the solution set, we will only show the overlapping region.