Big Ideas Math Algebra 2, 2014
BI
Big Ideas Math Algebra 2, 2014 View details
7. Using Trigonometric Identities
Continue to next subchapter

Exercise 3 Page 517

Consider using the Pythagorean Identity sin ^2 θ + cos^2 θ = 1.

cos θ = 2sqrt(2)/3, tan θ = sqrt(2)/4, cot θ = 2sqrt(2), csc θ = 3, sec θ =3 sqrt(2)/4

Practice makes perfect

We want to find the values of the other five trigonometric functions of θ given that sin θ = 13 and 0 < θ < π2.

Finding cos θ

To find the value of cos θ, we will use one of the Pythagorean Identities. sin ^2 θ + cos^2 θ = 1We will substitute 13 for sin θ in the above equation and solve it for cos θ. Let's do it!
sin ^2 θ + cos^2 θ = 1
( 1/3)^2 + cos^2 θ= 1
cos ^2 θ = 1 -( 1/3 )^2
â–Ľ
Simplify right-hand side
cos ^2 θ = 1 - 1^2/3^2
cos ^2 θ = 1- 1/9
cos ^2 θ = 9/9 - 1/9
cos ^2 θ = 9-1/9
cos ^2 θ = 8/9
â–Ľ
Solve for cos θ
cos θ =± sqrt(8/9)
cos θ =± sqrt(8)/sqrt(9)
cos θ =± sqrt(8)/3
cos θ =± sqrt(4 * 2)/3
cos θ =± sqrt(4) * sqrt(2)/3
cos θ =± 2sqrt(2)/3
Be aware that we are told that θ lies between 0 and π2. Therefore, θ is in Quadrant I.
graph

In this quadrant, the cosine of θ is positive. Therefore, we will only keep the positive solution. cos θ = 2sqrt(2)/3

Finding the Other Trigonometric Ratios

Knowing that sin θ = 13 and cos θ = 2 sqrt(2)3, we are allowed to find the four remaining trigonometric ratios. Remember to simplify fractions and rationalize denominators, if needed.

Function Substitute Simplify
tan θ=sin θ/cos θ tan θ=13/2sqrt(2)3 tan θ = sqrt(2)/4
cot θ=cos θ/sin θ cot θ=2sqrt(2)3/13 cot θ=2sqrt(2)
csc θ=1/sin θ csc θ=1/13 csc θ=3
sec θ=1/cos θ sec θ=1/2sqrt(2)3 sec θ=3sqrt(2)/4

Showing Our Work

Simplifying Fractions and Rationalizing Denominators
Simplifying the above fractions requires different methods for each case. Let's start with cot θ.
cot θ = 2sqrt(2)3/13
â–Ľ
Simplify right-hand side
cot θ = 2sqrt(2)/1
cot θ = 2sqrt(2)
To simplify tan θ and sec θ, we need to rationalize the denominators. Let's look at how this was done for tan θ first.
tan θ=13/2sqrt(2)3
â–Ľ
Simplify right-hand side
tan θ=1/2sqrt(2)
tan θ=sqrt(2)/2sqrt(2)* sqrt(2)
tan θ=sqrt(2)/2(sqrt(2))^2
tan θ=sqrt(2)/2(2)
tan θ=sqrt(2)/4
Let's now follow a similar procedure to rationalize the denominator of sec θ.
sec θ = 1/2sqrt(2)3
â–Ľ
Simplify right-hand side
sec θ = 3/2sqrt(2)3 * 3
sec θ = 3/2sqrt(2)
sec θ=3sqrt(2)/2sqrt(2)* sqrt(2)
sec θ=3sqrt(2)/2(sqrt(2))^2
sec θ=3sqrt(2)/2(2)
sec θ=3sqrt(2)/4