Big Ideas Math Algebra 2, 2014
BI
Big Ideas Math Algebra 2, 2014 View details
5. Using Recursive Rules with Sequences
Continue to next subchapter

Exercise 8 Page 443

Pay close attention to how the consecutive terms are related.

a_1=1, a_2=2, a_n=a_(n-1) * a_(n-2)

Practice makes perfect

We want to write a recursive rule for the given sequence. To do that, we first need to identify whether the given sequence is arithmetic, geometric, or neither. To do so we will calculate the difference and ratio between consecutive terms.

We can see above that neither the ratios nor the differences are the same. Therefore, the sequence is neither geometric nor arithmetic, so we have to look for another pattern. To do so we need to consider how the consecutive terms are related. Let's take a look at the quotients between pairs of consecutive terms. ccccc a_1&=& 1 [1.2em] a_2&=& 2 [1.2em] a_3/a_2&=& 2/2 &=& 1 [1.2em] a_4/a_3&=& 4/2&=& 2 [1.2em] a_5/a_4&=& 8/4&=& 2 [1.2em] a_6/a_5&=& 32/8&=& 4 [2em] ... & & ... & & ...

a_n/a_(n-1) = a_(n-2)

We can see above that the quotient between the consecutive terms equals a_(n-2). Therefore, to obtain the value of the term in the n^(th) position, we need to multiply two previous terms a_(n-1) and a_(n-2). With this information and knowing that the first and second term equal 1 and 2 we can write the recursive formula. a_1=1, a_2=2, a_n=a_(n-1) * a_(n-2)