The numbers Tn are represented by the points of following diagrams.
b Of course, the first triangular number is T1=1.
Notice that the number of dots in Tn is n more than the number of dots in Tn−1. Therefore, we can write a recursive rule for Tn.
c Of course T1=S1. Now, let's analyze the situation when n>1. Notice that a square Sn can be divide into two smaller triangles, Tn and Tn−1, as in the following picture.
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