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Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
5. Using Recursive Rules with Sequences
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Exercise 6 Page 447

The given rule means that, after the first term of the sequence, every term f(n) is the product of the previous term f(n-1) and 12.

f(0)=10, f(1)=5, f(2)= 52, f(3)= 54, f(4)= 58, f(5)= 516

Practice makes perfect

We are asked to write the first 6 terms of a sequence, given a recursive rule. f(0)&=10 f(n)&=1/2f(n-1) To do so, we will use a table.

n f(n)=1/2f(n-1) 1/2f(n-1) f(n)
0 f( 0)=10 - 10
1 f( 1)=1/2f( 1-1) 1/2 f(0)=1/2( 10) 5
2 f( 2)=1/2f( 2-1) 1/2 f(1)=1/2( 5) 5/2
3 f( 3)=1/2f( 3-1) 1/2 f(2)=1/2( 5/2) 5/4
4 f( 4)=1/2f( 4-1) 1/2 f(3)=1/2( 5/4) 5/8
5 f( 5)=1/2f( 5-1) 1/2 f(4)=1/2( 5/8) 5/16

Therefore, the first 6 terms of the sequence are 10, 5, 52, 54, 58 and 516.

Subchapter links expand_more
arrow_right Communicate Your Answer p.441
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arrow_right Monitoring Progress p.442-446
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Monitoring Progress 2 (Page 442)
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