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Explanation: See solution.
(a-b)^2=a^2-2ab+b^2
a * 1=a
1^a=1
Distribute 2
Subtract term
Let's go through these steps one at a time.
g(x)=a(x-p)(x-q) In this form, where a ≠0, the x-intercepts are p and q. Let's consider the intercept form of our function. g(x)=2x(x-2) ⇕ g(x)= 2(x- 0)(x- 2) We can see that a= 2, p= 0, and q= 2. Therefore, the x-intercepts occur at ( 0,0) and ( 2,0).
The axis of symmetry is halfway between (p,0) and (q,0). Since we know that p=0 and q=2, the axis of symmetry of our parabola is halfway between (0,0) and (2,0). x=p+q/2 ⇒ x=0+ 2/2=2/2=1 We found that the axis of symmetry is the vertical line x=1.
Finally, we will draw the parabola through the vertex and the x-intercepts.