Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
5. Using Intercept Form
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Exercise 75 Page 456

Recall the general factored form of a cubic function and use the given points to find its equation.

Sample Answer: f(x)=x^3-8x^2+7x

Practice makes perfect

We want to find a cubic function that satisfies the given conditions. Let's think about what the given information tells us.

  • A cubic function is a 3-degree function — this degree tells us that the function can have one or three real zeros.
  • The function passes through (1,0) and (7,0) — this tells us the location of two of the real zeros.
Using the general form of a factored cubic equation, we can write the factored form of a cubic function that passes through the given points. f(x)=a(x-p)(x-q)(x-r)In the above equation, p, q, and r are the x-intercepts of the function. We are told that the points ( 1,0) and ( 7,0) lie on the graph. Therefore, 1 and 7 are roots of the equation. f(x)=a(x- 1)(x- 7)(x-r) Since we do not know the third root, we can choose whatever r we want. For simplicity, let r= f(x)=a(x- 1)(x- 7)(x- ) ⇕ f(x)=ax(x-1)(x-7) Since a does not have any effect on the roots, we can choose any value. For simplicity, we will let a= 1. f(x)= 1x(x-1)(x-7) ⇕ f(x)=x(x-1)(x-7) Finally, let's rewrite the function in order to obtain its standard form.
f(x)=x(x-1)(x-7)
f(x)=(x^2-x)(x-7)
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Multiply parentheses
f(x)=x^2(x-7)-x(x-7)
f(x)=x^3-7x^2-x(x-7)
f(x)=x^3-7x^2-x^2+7x
f(x)=x^3-8x^2+7x
Note that this is only one of the infinitely many functions with the given characteristics. Any function passing through (1,0) and (7,0) will be correct.